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- by Ashok Shah 4 months ago

Let AB the diameter of the circle with center O where A(x_{1}, y_{1}) and B(x_{2}, y_{2}) are the end-points of the diameter.

Let P be any point on the circumference of the circle. Then, AP and BP is joined such that triangle ABP is formed as shown in the figure.

Then,

angle APB = 90^{O } [angle at semi-circle is right angle]

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