simultaneous equation

x+3y=2 and y^2+x=xy=y

0  Views: 1075 Answers: 2 Posted: 9 years ago

x+3y=2 and y^2+x=xy=y

If xy = y, then one of those must be equal to 1
IF X = 1, then 1 + 3y = 2, which mean y = 1/3
IF that is true, then let's see how y^2 + x looks: (1/3)^2 + 1 = 1//6 + 1 = 1 /6 (That doesn't work)

So, Y must = 1.
x +3(1) = 2, so x must be (-1) because (-1) + 3(1) = 2
Let's see if that follows through with the rest of the equation.

1^2 + (-1) = (-1)(1) = 1   and that doesn't work, either, because 1 doesn't = (-1)
So, I suggest you look it up with a Google search or pay attention to someone else's answer.  :(

Such type of equation is non-deterministic equation.

Since, though there are two unknown variables but more than two equations to solve them.

From such kind of equations, we get the wrong result.

So, be careful from next time with such kind of solution before attempting it.

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