ijairath
1 Answer
Deleted User
A geometric progression sum: 1/1-r (assuming sequence is r, r^2,...r^n
? this is only valid when you take the limit of the sum of a geometric sequence as {n\rightarrow\infty}, and you need to have the first term of the sequence on the numerator, unless it is exactly 1.
that is
\lim_{n\rightarrow\infty}S_n=\lim_{n\rightarrow\in fty}b_1\frac{1-q^{n}}{1-q}=\frac{b_1}{1-q} for |q|<1 and
\lim_{n\rightarrow\infty}S_n=\infty when |q|>1
| 12 years ago. Rating: 1 | |
Top contributors in Uncategorized category
Unanswered Questions
soc88vipco
Answers: 0
Views: 1
Rating: 0
nhandinhkeonhacai1
Answers: 0
Views: 1
Rating: 0
VB777
Answers: 0
Views: 2
Rating: 0
tylekeo365
Answers: 0
Views: 5
Rating: 0
bj388
Answers: 0
Views: 5
Rating: 0
bj388
Answers: 0
Views: 3
Rating: 0
nhaxetholam
Answers: 0
Views: 6
Rating: 0
bongdalucx
> More questions...
Answers: 0
Views: 5
Rating: 0