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    simplify following logic expression- i) B(A+C)+AB'+BC'+C

    0  Views: 313 Answers: 1 Posted: 7 years ago
    Tags: hexadecimal

    1 Answer

    B(A+C)+AB'+BC'+C


    Substitute numbers for A, B, and C. 


    A = 2, B = 3, C = 5


    3(2 + 5) + (2 x 3) + (3 x 5) + 5


    3(7) + 6 + 15 + 5


    21 + 6 + 15 + 5


    27 + 20 


    47


    B(A+C)+AB'+BC'+C


    (BA) + (BC) + AB + BC + C


    2BA (AB and  BA are the same) + 2BC  + C


    2AB + 2BC + C


    (Now let's see if that's the same with the digits in there)


    2 (2 x 3) + 2 (3 x 5) + 5


    2 (6) + 2 (15) + 5


    12 + 30 + 5 = 47


    Yep, the bold type is correct

    Kayce Bee

    that line before the BOLD andswer do i write that in sentence like how you did or ?
    Bob/PKB

    The part above the bold with the unknowns (ABC) is how to solve the equation. I substituted the 2, 3, and 5 to validate my answer. I should have done the ABC first, then substituted the numbers to prove it.
    I enjoy explaining (or trying to) how this kind of stuff works. It was impossible for me when I was in high school, but it mostly makes sense to me 100 years later :D
    If you would like more explanation, ask one of our moderators to give you my email address.


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