# 1 Answer

B(A+C)+AB'+BC'+C

Substitute numbers for A, B, and C.

A = 2, B = 3, C = 5

3(2 + 5) + (2 x 3) + (3 x 5) + 5

3(7) + 6 + 15 + 5

21 + 6 + 15 + 5

27 + 20

47

B(A+C)+AB'+BC'+C

(BA) + (BC) + AB + BC + C

2BA (AB and BA are the same) + 2BC + C

**2AB + 2BC + C**

(Now let's see if that's the same with the digits in there)

2 (2 x 3) + 2 (3 x 5) + 5

2 (6) + 2 (15) + 5

12 + 30 + 5 = 47

Yep, the bold type is correct

7 years ago. Rating: 3 | |

that line before the BOLD andswer do i write that in sentence like how you did or ?

The part above the bold with the unknowns (ABC) is how to solve the equation. I substituted the 2, 3, and 5 to validate my answer. I should have done the ABC first, then substituted the numbers to prove it.

I enjoy explaining (or trying to) how this kind of stuff works. It was impossible for me when I was in high school, but it mostly makes sense to me 100 years later :D

If you would like more explanation, ask one of our moderators to give you my email address.

I enjoy explaining (or trying to) how this kind of stuff works. It was impossible for me when I was in high school, but it mostly makes sense to me 100 years later :D

If you would like more explanation, ask one of our moderators to give you my email address.

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