close
    gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy

    hear are some conversions factors 0.911 ounce


     

    0  Views: 2959 Answers: 1 Posted: 13 years ago

    1 Answer

    Solution:
    1 glonkin equals 0.911 troy ounces, which equal 28.3352674 grams. Thus, 100 glonkins are 2833.52674 grams.
    If gold's density is 19.3g/ml, 2833.52674 grams divided by 19.3 will give the number of ml that 2833.52674 grams of gold occupy:
    2833.52674 / 19.3 = 146.815 ml, approximately.
    146.815 ml = 0.147 liters, approximately.



    Top contributors in Chemistry category

     
    ROMOS
    Answers: 66 / Questions: 0
    Karma: 3315
     
    country bumpkin
    Answers: 43 / Questions: 0
    Karma: 2625
     
    Colleen
    Answers: 112 / Questions: 0
    Karma: 2220
     
    Benthere
    Answers: 2 / Questions: 0
    Karma: 1440
    > Top contributors chart

    Unanswered Questions

    king88: Diem den ly tuong cho cuoc thu dam me
    Answers: 0 Views: 13 Rating: 0
    71BR Site Oficial de Slots
    Answers: 0 Views: 21 Rating: 0
    2b8news
    Answers: 0 Views: 57 Rating: 0
    keonhacai5sa
    Answers: 0 Views: 58 Rating: 0
    go88 go88
    Answers: 0 Views: 83 Rating: 0
    barrywhiteus
    Answers: 0 Views: 89 Rating: 0
    barrywhiteus
    Answers: 0 Views: 87 Rating: 0
    barrywhiteus
    Answers: 0 Views: 87 Rating: 0
    > More questions...
    509877
    questions
    752016
    answers
    851346
    users