close
    gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy

    hear are some conversions factors 0.911 ounce


     

    0  Views: 2950 Answers: 1 Posted: 13 years ago

    1 Answer

    Solution:
    1 glonkin equals 0.911 troy ounces, which equal 28.3352674 grams. Thus, 100 glonkins are 2833.52674 grams.
    If gold's density is 19.3g/ml, 2833.52674 grams divided by 19.3 will give the number of ml that 2833.52674 grams of gold occupy:
    2833.52674 / 19.3 = 146.815 ml, approximately.
    146.815 ml = 0.147 liters, approximately.



    Top contributors in Chemistry category

     
    ROMOS
    Answers: 66 / Questions: 0
    Karma: 3315
     
    country bumpkin
    Answers: 43 / Questions: 0
    Karma: 2625
     
    Colleen
    Answers: 112 / Questions: 0
    Karma: 2220
     
    Benthere
    Answers: 2 / Questions: 0
    Karma: 1440
    > Top contributors chart

    Unanswered Questions

    Giải vô địch quốc gia
    Answers: 0 Views: 4 Rating: 0
    Giải vô địch quốc gia
    Answers: 0 Views: 2 Rating: 0
    Giải vô địch quốc gia
    Answers: 0 Views: 5 Rating: 0
    Nhà Cái Uy Tín
    Answers: 0 Views: 4 Rating: 0
    vozolestonia
    Answers: 0 Views: 8 Rating: 0
    5679 eu
    Answers: 0 Views: 9 Rating: 0
    Đội tuyển quốc gia
    Answers: 0 Views: 11 Rating: 0
    33win99 Dev
    Answers: 0 Views: 13 Rating: 0
    > More questions...
    502180
    questions
    745060
    answers
    840876
    users