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    gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy

    hear are some conversions factors 0.911 ounce


     

    0  Views: 2868 Answers: 1 Posted: 11 years ago

    1 Answer

    Solution:
    1 glonkin equals 0.911 troy ounces, which equal 28.3352674 grams. Thus, 100 glonkins are 2833.52674 grams.
    If gold's density is 19.3g/ml, 2833.52674 grams divided by 19.3 will give the number of ml that 2833.52674 grams of gold occupy:
    2833.52674 / 19.3 = 146.815 ml, approximately.
    146.815 ml = 0.147 liters, approximately.



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