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    solve for y: 3y-2(y-1)/6=-1

    0  Views: 838 Answers: 3 Posted: 7 years ago

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    solve for y: 3y-2(y-1)/6=-1


    3y - 2y +2/6 = -1


    y + 1/3 = -1

    y = -1 1/3


    solve for y: 3y-2(y-1)/6=-1


    3 (-1 1/3) - 2(-1 1/3) +2 /6 = -1


    -4 + 2 2/3 + 2/6 = -1


    -1 1/3 + 1/3 = - 1


     

    chelleanne

    Check my answer: Did I do this right?
    chelleanne

    I agree! I worked the problem the way you did it first. Then worked it the other way. The divided by 6 (how it's written) got me confused.

    3y-2(y-1)/6=-1


    3y - (2y - 2)  = -1


                6


    3y - 1/3y + 1/3  = -1


    9/3y - 1/3y  + 1/3 = -1 


    8/3y + 1/3 = -1


    8/3y + 1/3 - 1/3 = -1 - 1/3


                                    -3/3 - 1/3 = - 4/3


    8/3y = -4/3


    8/3 / 8/3 = -4/3 * 3/8


    y = -1/2

    Bob/PKB

    I would trust your answer more than mine, and I wonder if the whole thing should be divided by 6? That would make it:
    1y + 2 / 6 = -1
    1/6y + 1/3 = -1
    y + 2 = -6
    y = -4
    (The way the division is added in at the end is where I get messed up.) I'll check with someone who knows and get back to you.... your answer looks good to me, but so do both of mine. :o
    Bob/PKB

    Eggplant could answer this. Hope she finds it and sets us straight! Have a good weekend :D

    3y-2(y-1)/6=-1


    or, (18y - 2y +2 )/6 = -1


    or, 16 y +2 = -6


    or, 16 y = -8


    or, y = -8/16


    or, y = -1/2


    Hope you got your answer.



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