solve for y: 3y-2(y-1)/6=-1

0  Views: 918 Answers: 3 Posted: 10 years ago

solve for y: 3y-2(y-1)/6=-1

3y - 2y +2/6 = -1

y + 1/3 = -1

y = -1 1/3

# solve for y: 3y-2(y-1)/6=-1

3 (-1 1/3) - 2(-1 1/3) +2 /6 = -1

-4 + 2 2/3 + 2/6 = -1

-1 1/3 + 1/3 = - 1

chelleanne

Check my answer: Did I do this right?
chelleanne

I agree! I worked the problem the way you did it first. Then worked it the other way. The divided by 6 (how it's written) got me confused.

# 3y-2(y-1)/6=-1

3y - (2y - 2)  = -1

6

3y - 1/3y + 1/3  = -1

9/3y - 1/3y  + 1/3 = -1

8/3y + 1/3 = -1

8/3y + 1/3 - 1/3 = -1 - 1/3

-3/3 - 1/3 = - 4/3

8/3y = -4/3

8/3 / 8/3 = -4/3 * 3/8

y = -1/2

Bob/PKB

I would trust your answer more than mine, and I wonder if the whole thing should be divided by 6? That would make it:
1y + 2 / 6 = -1
1/6y + 1/3 = -1
y + 2 = -6
y = -4
(The way the division is added in at the end is where I get messed up.) I'll check with someone who knows and get back to you.... your answer looks good to me, but so do both of mine. :o
Bob/PKB

Eggplant could answer this. Hope she finds it and sets us straight! Have a good weekend :D

3y-2(y-1)/6=-1

or, (18y - 2y +2 )/6 = -1

or, 16 y +2 = -6

or, 16 y = -8

or, y = -8/16

or, y = -1/2

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