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The theoretical yield of ammonia if 14.29 grams of nitrogen gas and 10.85 grams of hydrogen react:
the equation or the reaction is N2 + 3 H2 ----> 2 NH3
number nitrogen moles: given mass divided by nitrogen molar mass: 14.29/14 = 1 mole of N2.
The same process for hydrogen moles calculation: 10.85 / 1 = 10.85 moles of H2 molecule.
Insertion of the calculated molar values into the original equation:
1N2 + 10 H2 ----> 1 NH3
The theoretical yield of ammonia is 1 mole.
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