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    how do you solve linear system equations?

    0  Views: 454 Answers: 2 Posted: 13 years ago

    2 Answers

    Check here>>>http://www.ehow.com/how_4501267_solve-linear-systems-algebraically.html

    Hi:


     


    there are three ways to solve a linear  systems of equations:


    1. Graph it - very cude but will yield good answers


    2) substitution - better than number 1


    3 Elimination - Best method for find the answer


     


    Example for substitution (#2)   :


    Given:


    x+ 1 = y


    2x+3 = y


    x+1 = 2x +3 - substitution


    -x + x +1 = 2x+3 + - x   -  Adding the additive inverse of a variable to both sides of the equation to move it to the other side of it


    1= x+3 - Addition  


    -3+ 1 =x + 3 + -3 -  Adding the additive inverse of a number to both sides of the equation to move it to the other side of it


    -2 = x - Addition  


     Let solve for y 


    x+ 1 = y - one of the given equation from the above


    -2 + 1 = y - substituting x with -2


    -1 = y - Addition


    solution is - 2, -1


    Proof:


    Given :


    x+ 1 = y


    2x+3 = y


    step 2


    -2+ 1 = -1


    2(-2)+3 = -1- substituting xwith -2 and y with -1


    step 3:


    -2+1 = -1


    -4+3 = -1 - multiplication of -2 and 2


    -1 = - 1


    -1 = -1 - Addition


    It checks and equals


     


    Example for Elimination  (#3)   :


    Given:


    x+ 1 = y


    2x+3 = y


    Step 1:


    I need a common multiple to cancel y to solve for x, -1  is good . So I'll use it


    step 2:


    (-1) x+ 1 = y( -1)


    2x+3 = y - Multiplying a negative number to one of the equation to both sides of it to change a coefficient from a negative value to a positive one or vise versa to cancel one of the terms to solve for the other though the addition of terms


    -x-1= - y


    2x+3= y


    -----------  -  Multiplication and addition of terms


    x +2 = 0


    x+ 2 + -2 =0 + -2 -  Adding the additive inverse of a number to both sides of the equation to move it to the other side of it


    x = -2  - Addition


    step 3:


    let solve for y :


    x+ 1 = y


    2x+3 = y


    I need a common multiple to cancel x to solve for y,  -2  is good . So I'll use it


    (-2) x+ 1 = y (-2)


    2x+3 = y - Multiplying a negative number to one of the equation to both sides of it to change a coefficient from a negative value to a positive one or vise versa to cancel one of the terms to solve for the other though the addition of terms


    -2x-2 = -2y


    2x+3 = y


    ---------------- - Multiplication and addition of terms


    1 = - y 


    (-1)1= (-1)-y - Multiplying a negative number to both sides of the equation to
    remove a negative variable to get a positive variable


    -1 = y 


    solution ( -2,-1)


    I don't need the do the proof again since I really did it in the above


     


    However you will get one of three answer for a system of equations


    1) it as a solution


    2) there is no solution :due the fact they are a parrell line ( exp: y = 2x +1 ,y =  2x+3)


    3 there are a infinite number of soultions for it:  due the fact they are the same line ( example :


    2x + 3 = y  , 4x+ 6 = 2y )


     


    I hope this helps


     


     


     



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