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    2y2+3y+1/2y2-5y-3

    0  Views: 551 Answers: 2 Posted: 14 years ago

    2 Answers

    http://www.mathscore.com/math/practice/Simplifying%20Algebraic%20Expressions/

    2y2 + 3y + 1/2y2 - 5y -3 = 0
    2.5y2 - 2y - 3 = 0
    Multiply by 2 in order to get rid of incomplete numbers.
    5y2 - 4y - 6 = 0
    Finding the two solutions of the quadratic equation by the quadratic formula


    x=\frac{-b \pm \sqrt {b^2-4ac}}{2a},
    y1 = [4 + √(16 - 4 x 5 x -6)] / 2 x 5= 4 + 11.6619037896906 = 15.6619037896906
    y2 = [4 - √(16 - 4 x 5 x -6)] / 2 x 5= 4 - 11.6619037896906 = -7.6619037896906 



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