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    f(x)=sqrt(x,-5)

    0  Views: 564 Answers: 1 Posted: 13 years ago

    1 Answer

    y = sqrt [x - 5]


    Squaring


    y^2 = x - 5


    y^2 + 5 = x


    x = y^2 + 5


    Replacing y by x on right side


    Inverse function: x^2 + 5


    ...........


    For the domain of sqrt [x - 5], it has to be x > = 5, because if x < 5, the function would become negative and u can not take square root of a negative term. So, domain of f(x) is x > = 5.


    The domain of the function = range of the inverse.


    So, range of the inverse is Range > = 5.


    ...............


    Range of the function is that it is > = 0. (This is the domain of the inverse also) http://answers.yahoo.com/question/index?qid=20100325220106AAWLdP1



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