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    what is the impedance if i connect two 8 ohm speakers together

    if i have two 8 ohm speakers in one cabinet that are wired together what will the impedance be and are the speakers wired in parrallel or in series

    +1  Views: 571 Answers: 2 Posted: 11 years ago

    2 Answers

    According to imformation posted on the internet, impedance is calculated as follows:
    1 / [(1/I3) + (1/I2) + (1/I3) + ...]
    'I' repressents the impedance of individual speakers. In your case, the calculation is
    1 / [(1/8) + (1/8)] = 4.
    Another way to calculate impedance if the loads are eight or four ohms is as follows:
    impedance = 8 / n. n is the number of 8 ohm speakers plus twice the number of 4 ohm speakers.

    Parrellel,



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