close
    The perimeter of a rectangle is 206 inches, the length exceeds the width by 29 inches. Find thge length and the width. the length is

    0  Views: 1084 Answers: 1 Posted: 12 years ago

    1 Answer

    your home work is to figure out how I did it...


    width is 37 length is 66        37X2+66X2=206

    chelleanne

    Just stumble upon this question.
    Did you do it this way?

    Set up two equations:

    L = Length
    W = Width

    2L + 2W = 206
    L = W + 29

    Solve for W

    2(W + 29) + 2W = 206
    2W + 58 + 2W = 206
    4W + 58 = 206
    4W + 58 - 58 = 206 - 58
    4W = 148
    4W/4 = 148/4
    W = 37

    Solve for L. Use either equation

    L = W + 29
    L = 37 + 29
    L = 66

    L = 66
    W = 37

    P = 66*2 + 37*2 = 206





    Top contributors in Uncategorized category

     
    ROMOS
    Answers: 18061 / Questions: 154
    Karma: 1101K
     
    Colleen
    Answers: 47270 / Questions: 115
    Karma: 953K
     
    country bumpkin
    Answers: 11322 / Questions: 160
    Karma: 838K
     
    Benthere
    Answers: 2392 / Questions: 30
    Karma: 760K
    > Top contributors chart

    Unanswered Questions

    Dr Sơn Quang Chuyên Hút Mỡ, Nâng Ngực
    Answers: 0 Views: 7 Rating: 0
    betvisanews
    Answers: 0 Views: 8 Rating: 0
    Agen234 Slot Online
    Answers: 0 Views: 7 Rating: 0
    Agen234 Slot Online
    Answers: 0 Views: 6 Rating: 0
    Agen234 Slot Online
    Answers: 0 Views: 8 Rating: 0
    Mksport
    Answers: 0 Views: 8 Rating: 0
    event management companies in greater noida ?
    Answers: 0 Views: 6 Rating: 0
    > More questions...
    452289
    questions
    719720
    answers
    754160
    users