4[(x-2) + 5] -3x = -2(x+5) - 4x

        (x -2 + 5) - 3x

            (x + 3) - 3x

           4(x + 3) - 3x  

            4x + 12 - 3x  >  4x + -3x + 12 = x + 12

Left side:  x + 12

-2(x + 5) - 4x

-2x - 10 - 4x  >  -2x + -4x - 10 = -6x - 10

Right side:  -6x - 10

Put the problem back together with the calculations of the right and left sides.

     x + 12 = -6x - 10  >  cancel out -6x on the right by adding +6x to the left.

                                        cancel out +12 on the left by subtracting -12 to the right

x + 6x  + 12 - 12 =  -6x + 6x  - 10 - 12

                   0                   0

                      7x    =    -22

                      7/7   =   -22/7

                         x    =    -22/7

I hated algebra!!!

one of my  favorite subjects :(

-5x

5x