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    3. 2y2+3y+1/2y2-5y-3=
    2y2+3y+1/2y2-5y-3=

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    0  Views: 313 Answers: 1 Posted: 14 years ago
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      1 Answer

      2Y^2+3Y+1/2Y^2-5Y-3=0


      3/2Y^2-2Y-3=0


      Y,1,2={2+/-sqrt(4-4*3/2*(-3))}/2*2.5={2+/-sqrt(34)}/5


      Y1=1.5662


      Y2=-0.7662

      14 years ago. Rating: 0
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