2 Answers
x+3y=2 and y^2+x=xy=y
If xy = y, then one of those must be equal to 1
IF X = 1, then 1 + 3y = 2, which mean y = 1/3
IF that is true, then let's see how y^2 + x looks: (1/3)^2 + 1 = 1//6 + 1 = 1 /6 (That doesn't work)
So, Y must = 1.
x +3(1) = 2, so x must be (-1) because (-1) + 3(1) = 2
Let's see if that follows through with the rest of the equation.
1^2 + (-1) = (-1)(1) = 1 and that doesn't work, either, because 1 doesn't = (-1)
So, I suggest you look it up with a Google search or pay attention to someone else's answer. :(
10 years ago. Rating: 2 | |
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