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    a coin bank contains twenty six nickels and quarters. the coins have a total value of $3.50. find the number of nickels and the number of quarters in the bank.

    0  Views: 559 Answers: 2 Posted: 11 years ago

    2 Answers

    n = nickels


    q = quarters


    n + q = 26


    q = 26 - n


    5n + 25q = 350   >  substitute first equation into this equation 


    _________________________________________


    5n + 25(26 - n) = 350


    5n + 650 - 25n = 350


    -20n + 650 = 350


             -650     -650   


    ________________________


    -20n  =  -300  


    _____     ______


     -20        -20


    n = 15


    Now solve for q. Use either equation.


    q = 26 - n


    q = 26 - 15


    q = 11

    In order to figure out the number of each coin, one need to define on of them as y (for instance) and the other as 26-y.
    The initial equation is: 26 x [ 0.05y + 0.25 x (26 - y) ] = 3.5.



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